सी स्रोत कोड/मैट्रिक्स गुणन

/* Program to implement matrix multiplication. */
/* Performed by Milan. */
/* Edited by Gergo: resolved some portability issues */

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
        int a[10][10], b[10][10], c[10][10];
        int i, j, m, n, x, y, k;

        /* Entering values for matrix a...*/
        printf ("\n Enter the rows and columns of a: ");
        scanf ("%d%d", &m, &n);

        for (i = 0; i < m; i++)
        {
                for (j = 0; j < n; j++)
                {
                        printf (" a[%d][%d] = ", (i+1), (j+1));
                        scanf ("%d", &a[i][j]);
                }
                printf ("\n");
        }

        /* Entering values for matrix b... */
        printf ("\n Enter the rows and columns of b: ");
        scanf ("%d%d", &x, &y);

        for (i = 0; i < x; i++)
        {
                for (j = 0; j < y; j++)
                {
                        printf (" b[%d][%d] = ", (i+1), (j+1));
                        scanf ("%d", &b[i][j]);
                }
                printf ("\n");
        }

        /* Calculations */
        if ( n != x)
        {
                printf ("\n Error!! Rows of a don't match with columns of b.");
                printf ("\n Multiplication Impossible.");
                exit(EXIT_FAILURE);
        }
        else
        {
                for (i = 0; i < m; i++)
                {
                        for (j = 0; j < y; j++)
                        {
                                c[i][j] = 0;
                                for (k = 0; k < n; k++)
                                {
                                        c[i][j]+=a[i][k]*b[k][j];
                                }
                        }
                }
        }

        /* Output */
        printf ("\n The resultant c is:\n");
        for (i = 0; i < m; i++)
        {
                for (j = 0; j < y; j++)
                {
                        printf (" c[%d][%d] = %d", (i+1), (j+1), c[i][j]);
                }
                printf ("\n");
        }

        return 0;
}
/* Output:

 Enter the rows and columns of a: 2 2
 a[1][1] = 1
 a[1][2] = 2

 a[2][1] = 3
 a[2][2] = 4

 Enter the rows and columns of b: 2 2
 b[1][1] = 2
 b[1][2] = 1

 b[2][1] = 2
 b[2][2] = 2

 The resultant c is:
 c[1][1] = 6 c[1][2] = 5
 c[2][1] = 14 c[2][2] = 11
*/